实现 trie 数据结构
trie数据结构的strider讲解
class node{
node [] node = new node[26];
boolean flag;
public node(){
}
public boolean containskey(char c){
return node[c-'a']!=null;
}
public void put(char c, node n){
node[c-'a'] = n;
}
public node get(char c){
return node[c-'a'];
}
public void setflag() {
this.flag = true;
}
public boolean getflag(){
return this.flag;
}
}
class trie {
node root;
public trie() {
root = new node();
}
//will take tc : o(len) of the word
public void insert(string word) {
node node = root;
for(int i =0;i
trie数据结构二
奋斗者的解释,以便更好理解
import java.util.* ; import java.io.*; class node { node node[] = new node[26]; int endwith = 0;// will keep track of no. of words ending with this word int countprefix=0;// will keep track of no. of words starting with this word public node(){ } public boolean containskey(char c){ return node[c-'a']!=null; } public void put(char c, node n){ node[c-'a'] = n; } public node get(char c){ return node[c-'a']; } public void incrementcountprefix() { ++this.countprefix; } public void decrementcountprefix(){ --this.countprefix; } public void incrementendwith(){ ++this.endwith; } public void deleteendwith(){ --this.endwith; } public int getcountprefix(){ return this.countprefix; } public int getendwith(){ return this.endwith; } } public class trie { node root; public trie() { // write your code here. root = new node(); } public void insert(string word) { node node = root; for(int i =0;i完整字符串
// tc : o(n*l) import java.util.* ; import java.io.*; class node{ node[] node = new node[26]; boolean flag; public node(){} public void put(char c , node n){ node[c-'a'] = n; } public boolean containskey(char c){ return node[c-'a']!=null; } public node get(char c){ return node[c-'a']; } public void setend(){ this.flag = true; } public boolean isend(){ return this.flag; } } class trie{ node root; public trie(){ root = new node(); } public boolean checkifprefixpresent(string s){ node node = root; boolean flag= true; for(int i = 0;i计算不同子串的个数
tc:在
中插入不同的唯一子字符串的 o(n^2) trie数据结构import java.util.ArrayList; public class Solution { Node root; static int count; public Solution(){ root = new Node(); } public static int countDistinctSubstrings(String s) { count = 0; // Write your code here. Solution sol = new Solution(); for(int i =0;i 登录后复制以上就是特里树的详细内容,更多请关注php中文网其它相关文章!
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